Linked List Cycle
Description
- Given
head
, the head of a linked list, determine if the linked list has a cycle in it.
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next
pointer. Internally, pos
is used to denote the index of the node that tail's next
pointer is connected to. Note that pos
is not passed as a parameter.
Return true
if there is a cycle in the linked list. Otherwise, return false
.
Constraints
- The number of the nodes in the list is in the range
[0, 10^4]
. -10^5 <= Node.val <= 10^5
pos
is-1
or a valid index in the linked-list.
Test Cases
-
Input:
head = [3,2,0,-4], pos = 1
Output:true
-
Input:
head = [1], pos = -1
Output:false
Code
Approach 1: Using slow and fast pointers
Explanation
- Initialize two pointers
slow
andfast
tohead
. - Move
slow
by one node andfast
by two nodes. - If
slow
andfast
meet, then there is a cycle. - Move
fast
tohead
and move bothslow
andfast
by one node. - If
slow
andfast
meet, then returnslow
.
Analysis
- Time Complexity:
O(n)
- Space Complexity:
O(1)