Linked List Cycle
Description
- Given
head, the head of a linked list, determine if the linked list has a cycle in it.
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next pointer. Internally, pos is used to denote the index of the node that tail's next pointer is connected to. Note that pos is not passed as a parameter.
Return true if there is a cycle in the linked list. Otherwise, return false.
Constraints
- The number of the nodes in the list is in the range
[0, 10^4]. -10^5 <= Node.val <= 10^5posis-1or a valid index in the linked-list.
Test Cases
-
Input:
head = [3,2,0,-4], pos = 1
Output:true -
Input:
head = [1], pos = -1
Output:false
Code
Approach 1: Using slow and fast pointers
Explanation
- Initialize two pointers
slowandfasttohead. - Move
slowby one node andfastby two nodes. - If
slowandfastmeet, then there is a cycle. - Move
fasttoheadand move bothslowandfastby one node. - If
slowandfastmeet, then returnslow.
Analysis
- Time Complexity:
O(n) - Space Complexity:
O(1)